Tyreek Hill wins AFC Offensive Player award for Week 12
By Matt Conner
Tyreek Hill won the AFC’s Offensive Player of the Week award after setting personal highs against the Buccaneers.
Kansas City Chiefs wide receiver Tyreek Hill was named the AFC Offensive Player of the Week for his Week 12 performance against the Tampa Bay Buccaneers in which he set or tied new highs in multiple categories.
Hill wasted no time turning heads on Sunday with an electric first quarter that featured two deep scores from Chiefs quarterback Patrick Mahomes. Before the first 15 minutes were over, the Chiefs were up 17-0 and Hill already had 200 yards receiving on the day. By game’s end, Hill had caught 13 of 15 targets thrown his way for an incredible 269 receiving yards and 3 touchdowns. The yardage set a new career high and his three scores on the day also matched a career-high as well.
On the year, Hill has five full games to go yet he’s already crossed the 1,000 yard mark as a receiver in 11 games. Hill has 68 catches for 1,021 yards and 13 touchdowns through the air. He also has another rushing touchdown and 60 yards on the ground.
Hill is the Chiefs all-time single-season leader in receiving yards, a mark set during his monster 2018 campaign in which he put up 1,479 receiving yards. Given the pace he’s on this year, he’s also on track to set the Chiefs single-season record for most touchdown receptions in a year, currently held by Dwayne Bowe and his 15 touchdowns which led the NFL back in 2010.
his last four games, Hill is on a particularly torrid pace with 8 touchdowns and 582 receiving yards. He’s well on his way to making his fifth Pro Bowl in five NFL seasons and if he keeps it up, he’s likely going to find himself immortalized in Canton one day in the Pro Football Hall of Fame.