For his efforts against the Cleveland Browns, K.C. Chiefs quarterback Patrick Mahomes has been named the AFC’s Offensive Player of the Week.
Mahomes willed the Chiefs back into the game after being down 22-10 at halftime to put away the Browns by a finals score of 33-29, and Mahomes himself was involved in all four touchdowns.
Mahomes had three touchdown passes and one rushing score, an impressive red zone scramble in the first half that kept pace with the Browns. Mahomes also found Tyreek Hill on an incredible 75-yard touchdown pass that changed the game’s momentum, and the ever-reliable Travis Kelce was the recipient of the other two touchdown throws from Mahomes to round out the afternoon.
Patrick Mahomes was honored for his production against the Browns in Week 1.
Mahomes finished the game with a final line of 27 completions on 36 attempts for 337 yards and an impressive 9.4 yards/attempt average. He had a passer rating of 131.4 for the entire game.
For Mahomes, it’s an impressive start to his fourth season under center for the Chiefs, and he’s never finished lower than second in Most Valuable Player voting since taking over the role from Alex Smith as the team’s starting quarterback. The competition will be tough again, after losing consecutive awards to Lamar Jackson and Aaron Rodgers, but these weekly awards easily add up to MVP numbers by season’s end.
As for other winners, pass rusher Maxx Crosby was named the AFC’s Defensive Player of the Week for his incredible performance against the Baltimore Ravens in a surprising overtime win. Kicker Evan McPherson of the Cincinnati Bengals put his team over the top in overtime as well and deserved the Special Teams Player of the Week for the AFC.