Jamaal Charles Wins AFC Offensive Player Of The Week Award

John David Mercer-US PRESSWIRE

Jamaal Charles has been named the AFC Offensive Player of the Week award winner for his performance against the New Orleans Saints.

Charles went off on New Orleans, running for 233 yards while also pulling in six catches for 55 yards. Charles joined former Cleveland Browns great Jim Brown as the only player in league history to run for more than 225 yards while also exceeding 50 yards receiving, in a single game.

Congratulations to Jamaal and here’s hoping he can deliver a repeat performance on Sunday when the San Diego Chargers come to Arrowhead.

Topics: Jamaal Charles, Kansas City Chiefs

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  • ArrowFan

    He is my hero

  • RepOurChiefs

    I wear my #25 proudly…

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